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Proof step 2 from proof lastdiv (previous step)

⊦ x = [], ∃ y, a. x = y + a '

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 3:
x0 = [] ∨ (∃ y, a. x0 = y + a ') ⊦ a + x0 = [], ∃ y, a0. a + x0 = y + a0 '

Rule argument

term: x

Additional information

Used simplifier rules: list freely generated by [], +;;