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Proof step 4 from proof lastdiv (previous step)

x0 = [] ∨ x0 = y + a0 ' ⊦ ∃ y0, a1. a ' + x0 = y0 + a1 '

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 5:
x0 = y + (a0 + []), x0 = [] ∨ x0 = y + a0 ' ⊦ ∃ y0, a1. a ' + x0 = y0 + a1 '
Proof step 7:
x0 = [] ∨ x0 = y + a0 ' ⊦ x0 = y + (a0 + []), ∃ y0, a1. a ' + x0 = y0 + a1 '

Rule argument

fma: x0 = y + (a0 + [])

Additional information

Used formulas: x0 = y + (a0 + [])