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Proof step 1 from proof len-03 (conclusion)

⊦ a ' + x = y + b ' + z → ¬ # x < # z

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
a ' + x = y + b ' + z, # x < # z, a ∈ y ∨ a = b ∨ a ∈ z ⊦ z = []

Rule argument

Additional information

Used simplifier rules: in-14: ⊦ a ' + x = y → a ∈ y;%a: ⊦ (x + y) + z = x + y + z;%in-append: ⊦ a ∈ x + y ↔ ¬ ¬(a ∈ x ∨ a ∈ y);%in-rec: ⊦ a ∈ b ' + x ↔ ¬ ¬(a = b ∨ a ∈ x);%l: ⊦ # x = 0 ↔ x = []; from specification list-data%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1