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Proof step 1 from proof neq-04 (conclusion)

⊦ a ∈ y0 ∧ ¬ a ∈ y ∧ a ≠ b → y + b ' ≠ y0 + c ' + z

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inapp-11: ⊦ x + y = z + a ' ∧ b ∈ x ∧ a ≠ b → b ∈ z;%a: ⊦ (x + y) + z = x + y + z;%in-15: ⊦ x + a ' = y → a ∈ y;