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Proof step 1 from proof neq-09 (conclusion)

⊦ ¬ a ∈ y ∧ a ≠ c ∧ ¬ a ∈ z → y + c ' + z ≠ y1 + c ' + a ' + z0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: neq-01: ⊦ ¬ a ∈ y ∧ ¬ a ∈ z ∧ a ≠ c → y + c ' + z ≠ y1 + a ' + x;%a: ⊦ (x + y) + z = x + y + z;