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Proof step 12 from proof compl-monotone (
previous step
)
¬ f(λ x0. ¬ S0(x0))(x), S0 ⊆ S, ∀ S, S0. S ⊆ S0 → f(S) ⊆ f(S0) ⊦ compl(f)(S)(x)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 13
:
S0 ⊆ S, ∀ S, S0. S ⊆ S0 → f(S) ⊆ f(S0) ⊦ compl(f)(S)(x), f(λ x0. ¬ S0(x0))(x)
Rule argument
Additional information