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Proof step 27 from proof nu-is-UN (previous step)

S ⊆ f(S), S(x) ⊦ ∀ x. compl(f)(λ x0. ¬ S(x0))(x) → ¬ S(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
S(x0), compl(f)(λ x0. ¬ S(x0))(x0), S ⊆ f(S), S(x) ⊦

Rule argument

Additional information