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Proof step 8 from proof prefixpoint-aux-nu (previous step)

S(x), monotone(f), S ⊆ f(S) ⊦ ∃ S. S ⊆ f(S) ∧ S(x)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: S

Additional information

Used terms: S