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Proof step 6 from proof prefixpoint-aux (
previous step
)
∀ S. f(S) ⊆ S → S(x), monotone(f), f(S) ⊆ S ⊦ S(x)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 1 terms: S
Additional information
Used terms: S