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Proof step 3 from proof prefixpoint (
previous step
)
¬(∀ S. f(S) ⊆ S → f(μ(f)) ⊆ S), monotone(f) ⊦ f(μ(f)) ⊆ μ(f)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
f(S) ⊆ S, monotone(f) ⊦ f(μ(f)) ⊆ μ(f), f(μ(f)) ⊆ S
Rule argument
Additional information