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Proof step 8 from proof prefixpoint (
previous step
)
μ(f) ⊆ S, f(S) ⊆ S, ∀ S, S0. S ⊆ S0 → f(S) ⊆ f(S0) ⊦ f(μ(f)) ⊆ μ(f), f(μ(f)) ⊆ S
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 3 terms: μ(f), S
Additional information
Used simplifier rules: subset-trans: ⊦ S ⊆ S0 ∧ S0 ⊆ S1 → S ⊆ S1; Used terms: μ(f), S