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Proof step 11 from proof subset-trans (
previous step
)
S(x), S0(x) → S1(x), ∀ x. S0(x) → S1(x), ∀ x. S(x) → S0(x) ⊦ S1(x)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 12
:
S(x), ∀ x. S0(x) → S1(x), ∀ x. S(x) → S0(x) ⊦ S1(x), S0(x)
Rule argument
Additional information