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Proof step 8 from proof lrec (previous step)

∀ m. m +1 = n0 ∨ m +1 < n0 ↔ m < n0 ⊦ m = n0, m +1 = n0, m +1 < n0 ↔ m < n0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 9:
m +1 < n0, ∀ m. m +1 = n0 ∨ m +1 < n0 ↔ m < n0 ⊦ m = n0, m +1 = n0, m +1 < n0 ↔ m < n0
Proof step 11:
∀ m. m +1 = n0 ∨ m +1 < n0 ↔ m < n0 ⊦ m +1 < n0, m = n0, m +1 = n0, m +1 < n0 ↔ m < n0

Rule argument

fma: m +1 < n0

Additional information

Used formulas: m +1 < n0