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Proof step 2 from proof neq-01 (previous step)

⊦ m = n, n < m, m < n

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ n < m ∨ n = m ∨ m < n

Rule argument

spec: nat-basic1 inst: name: tot seq: ⊦ n < m ∨ n = m ∨ m < n subst: [m, n] → [n, m] flags: current, []

Additional information

Used terms: n, m