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Proof step 1 from proof one-02 (conclusion)

⊦ m ≠ 0 → (¬ 1 < m ↔ m = 1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: one: ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1);