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Proof step 2 from proof psu-02 (previous step)

⊦ n = 0, n -1 +1 = n

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: nat-basic1 inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n -1 ↔ n = m +1 subst: [n, m] → [n, m] flags: rewrite, current

Additional information

Used terms: n, m