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Proof step 1 from proof rax (conclusion)

⊦ n0 < n +1 ↔ ¬ ¬(n0 = n ∨ n0 < n)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: less-2: ⊦ n0 < n +1 ↔ n0 = n ∨ n0 < n;