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Proof step 5 from proof even-04 (previous step)

3 = 2 + 1, 2 + m0 + m0 = 3 ⊦ m0 + m0 = 3

User applied rule insert equation

And obtained the following new goals

Proof step 6:
2 + m0 + m0 = 2 + 1 ⊦ m0 + m0 = 2 + 1

Rule argument

pos: left 1 flags: discard

Additional information