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Proof step 3 from proof even (previous step)

∀ m. n0 + n0 = m + m → n0 = m, n0 +1 + n0 +1 = m + m ⊦ n0 +1 = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
2 + n0 + n0 = m + m, ∀ m. n0 + n0 = m + m → n0 = m ⊦ n0 + 1 = m

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;