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Proof step 7 from proof ex-oddeven (previous step)

⊦ ∃ m0. m0 + m0 = 2 + m + m

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: m + 1 abort: F discard: T computed: F

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%eq-01: ⊦ m + n = m + n0 ↔ n = n0; Used terms: m + 1