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Proof step 2 from proof l (previous step)

true, ∀ m1, n, n0. m1 < m → true → (m1 + n < m1 + n0 ↔ n < n0) ⊦ m + n < m + n0 ↔ n < n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ m1, n, n0. m1 < m → true → (m1 + n < m1 + n0 ↔ n < n0) ⊦ m + n < m + n0 ↔ n < n0

Rule argument

Additional information