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Proof step 6 from proof l (previous step)

∀ m, n1, n2. ¬ m0 < m → (m + n1 < m + n2 ↔ n1 < n2) ⊦ m0 + n < m0 + n0 ↔ n < n0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 7:
n < n0, ∀ m, n1, n2. ¬ m0 < m → (m + n1 < m + n2 ↔ n1 < n2) ⊦ m0 + n < m0 + n0 ↔ n < n0
Proof step 9:
∀ m, n1, n2. ¬ m0 < m → (m + n1 < m + n2 ↔ n1 < n2) ⊦ n < n0, m0 + n < m0 + n0 ↔ n < n0

Rule argument

fma: n < n0

Additional information

Used formulas: n < n0