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Proof step 8 from proof l (previous step)

n < n0, ∀ m, n1, n2. ¬ m0 < m → (m + n1 < m + n2 ↔ n1 < n2) ⊦ n0 = 0, m0 + n < m0 + n0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m0, n, n0

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: m0, n, n0