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Proof step 1 from proof less-01 (conclusion)

¬ n0 < n, ¬ n + m < m0 ⊦ ¬ n0 + m < m0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: l: ⊦ m + n < m + n0 ↔ n < n0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%lf-06: ⊦ ¬ m < n0 ∧ n < n0 → n < m; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1