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Proof step 1 from proof less-03 (conclusion)

¬ m0 < n1, n + n0 < m ⊦ n + n0 + n1 < m + m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n + n0 < m ⊦ m = 0, n + n0 + n1 < m + m0, m0 < n1

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1