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Proof step 1 from proof less-04 (conclusion)

m + m0 < n + n0, ¬ m < n ⊦ m0 < n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m + m0 < n + n0 ⊦ n + n0 = 0, m0 < n0, m < n

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1