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Proof step 1 from proof less-05 (conclusion)
m < m0, ¬ n0 < n ⊦ m + n < m0 + n0
User applied rule insert lemma
And obtained the following new goals
Proof step 2
:
¬ m0 < n0, n < m ⊦ n + n0 < m + m0
Rule argument
spec: nat-basic2 inst: name: less seq: ¬ m0 < n0, n < m ⊦ n + n0 < m + m0 subst: [n, n0, m, m0] → [m, n, m0, n0] flags: current, []
Additional information
Used terms: m, n, m0, n0