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Proof step 1 from proof neq (conclusion)

⊦ m < m0 ∧ n0 < n + m → n0 + 1 ≠ n + m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n0 + 1 = n + m0, m < m0, n0 < n + m ⊦ m0 = 0, n + m = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1