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Proof step 2 from proof one-02 (previous step)

m + n = 1 ⊦ m = 1, m = 0 ∧ n = 1

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: n

Additional information

Used simplifier rules: z: ⊦ 0 + m = m;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%succ: ⊦ m +1 = m + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%one-03: ⊦ 1 = m + 1 ↔ m = 0;%z-01: ⊦ m + n = 0 ↔ m = 0 ∧ n = 0;%c: ⊦ m + n = n + m;%nat freely generated by 0, +1;;