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Proof step 1 from proof pe-01 (conclusion)

⊦ m0 < m → n0 + (m + n)-1 = ((n0 + m) + n)-1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m0 < m ⊦ n0 + (m + n)-1 = ((n0 + m) + n)-1, m = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1