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Proof step 2 from proof ps (previous step)

⊦ m = 0, (m + n)-1 + 1 = m + n

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

spec: nat-basic1 inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n -1 ↔ n = m +1 subst: [n, m] → [m + n, m0] flags:

Additional information

Used simplifier rules: z-01: ⊦ m + n = 0 ↔ m = 0 ∧ n = 0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%succ: ⊦ m +1 = m + 1;%n ≠ 0 ⊦ m = n -1 ↔ n = m +1; (elim) Used terms: m + n, m0