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Proof step 2 from proof q (previous step)

⊦ ∃ n. 0 = n + n ∨ 0 = (n + n)+1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ ∃ n. 0 = n + n

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%oz: ⊦ m + 1 ≠ 0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;