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Proof step 1 from proof s (conclusion)

⊦ m < n + 1 ↔ ¬ n < m

Heuristic cut applied rule cut formula

And closed the goal!

Rule argument

fma: n < m

Additional information

Used simplifier rules: oz: ⊦ m + 1 ≠ 0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%succ: ⊦ m +1 = m + 1;%l-addone: ⊦ n < n + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%lf-07: ⊦ ¬ m < n ∧ ¬ n0 < m → ¬ n0 < n; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic1%trans-1: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic1%ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used formulas: n < m