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Proof step 2 from proof two-01 (previous step)

m + n = 2 ⊦ n = 0, m = 0, m = 1 ∧ n = 1

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ n. m0 + n = 2 → n = 0 ∨ m0 = 0 ∨ m0 = 1 ∧ n = 1, m0 +1 + n = 2 ⊦ n = 0, m0 +1 = 0, m0 +1 = 1 ∧ n = 1

Rule argument

term: m

Additional information

Used simplifier rules: nat freely generated by 0, +1;;