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Proof step 1 from proof ls-01 (conclusion)

n ≠ 0, m0 ≤ m, n ≤ n0 ⊦ m0 / n0 ≤ m / n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m / n < m0 / n0, n ≤ n0, m0 ≤ m ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat