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Proof step 4 from proof ls-01 (previous step)

m = m1 * n + n1 ∧ n1 < n, m1 < m0 / n0, n ≤ n0, m0 ≤ m ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n1 < n, m1 < m0 / n0, n ≤ n0, m0 ≤ m1 * n + n1, n1 < n0 ⊦

Rule argument

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; from specification nat-basic1