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Proof step 1 from proof ls-03 (conclusion)

n ≠ 0 ⊦ ¬ n0 / n + 1 < (n0 + n) / n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n0 / n + 1 < (n0 + n) / n ⊦ n = 0, (n0 + n) / n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1