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Proof step 27 from proof mod-by6 (previous step)

3 * n0 * n0 + (n0 * 2) * n0 * n0 + n0 = n * 6 ⊦ ((3 * n0 * n0 + (n0 * 2) * n0 * n0 + n0) + 6 * (n0 * n0 + 2 * n0)) % 6 = 0

User applied rule insert equation

And obtained the following new goals

Proof step 28:
⊦ (n * 6 + 6 * (n0 * n0 + 2 * n0)) % 6 = 0

Rule argument

pos: left 1 flags: discard

Additional information