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Proof step 30 from proof mod-by6 (previous step)

3 * n0 * n0 + (n0 * 2) * n0 * n0 + n0 = n * 6 ⊦ 9 * n0 * n0 + n0 * 13 + 2 * n0 * n0 * n0 = (3 * n0 * n0 + (n0 * 2) * n0 * n0 + n0) + 6 * (n0 * n0 + 2 * n0), (9 * n0 * n0 + n0 * 13 + 2 * n0 * n0 * n0) % 6 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%numeral-19: m2 ≠ 0 ⊦ (* m2) * m + n = m + n0 ↔ (m2 - 1) * m + n = n0; from specification nat-mult%numeral-01: m1 < m2 ⊦ (* m2) * m + n = (* m1) * m + n0 ↔ (m2 - m1) * m + n = n0; from specification nat-mult%eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult