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Proof step 5 from proof mod-once (previous step)

n * m / n ≤ m ⊦ n = 0, m - n * m / n = m % n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
n ≠ 0, m / n * n ≤ m ⊦ m % n = m - m / n * n

Rule argument

spec: nat-div inst: name: rax seq: n ≠ 0, m / n * n ≤ m ⊦ m % n = m - m / n * n subst: [n, m] → [n, m] flags: rewrite, current

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult Used terms: n, m