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Proof step 2 from proof mod-one-01 (previous step)

⊦ 1 % n = 1, n = 1, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ m < n → m % n = m

Rule argument

spec: nat-div inst: name: mod-eq seq: ⊦ m < n → m % n = m subst: [n, m] → [n, 1] flags: rewrite, current

Additional information

Used simplifier rules: one-02: ⊦ m ≠ 0 → (¬ 1 < m ↔ m = 1); from specification nat-basic1 Used terms: n, 1