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Proof step 4 from proof mod-succ-04 (previous step)

m = m0 * n + n0 ∧ n0 < n ⊦ (m + 1) % n < n0 ↔ (m + 1) % n = 0 ∧ n ≠ 1, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n0 < n ⊦ ((m0 * n + n0) + 1) % n < n0 ↔ ((m0 * n + n0) + 1) % n = 0 ∧ n ≠ 1, n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1