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Proof step 1 from proof mult-ls-01 (conclusion)

n ≠ 0 ⊦ n0 < m / n → n0 * n < m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n0 < m / n, m ≤ n0 * n ⊦ n = 0, m / n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat