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Proof step 1 from proof nummult-eq (conclusion)
n ≠ 0 ⊦ (* m) * m0 = (* n) ↔ n % m = 0 ∧ m0 = n / m ∧ m ≠ 0
Special step normalize
And obtained the following new goals
Proof step 2
:
n ≠ 0 ⊦ m * m0 = n ↔ n % m = 0 ∧ m0 = n / m ∧ m ≠ 0