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Proof step 7 from proof square-ls-03 (previous step)

(m * (m + 1)) / 2 + m0 = (m * (m + 1) + 2 * m0) / 2 ⊦ ¬ ((m + 1) * (m + 2)) / 2 ≤ ((n + 1) * (n + 2)) / 2, n < m, m0 ≤ m ∧ m ≤ n → (m * (m + 1)) / 2 + m0 < ((n + 1) * (n + 2)) / 2

User applied rule insert equation

And obtained the following new goals

Proof step 8:
⊦ ¬ ((m + 1) * (m + 2)) / 2 ≤ ((n + 1) * (n + 2)) / 2, n < m, m0 ≤ m ∧ m ≤ n → (m * (m + 1) + 2 * m0) / 2 < ((n + 1) * (n + 2)) / 2

Rule argument

pos: left 1 flags: discard

Proof step 7 from proof square-ls-03 (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information