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Proof step 8 from proof square-nle-01 (previous step)

m0 ≠ 0 ∧ m0 ≠ 1, n ≠ 0 ∧ n ≠ 1, n * n + n = m0 * 2 + n0, n0 < 2 ⊦ m0 ≤ n ↔ n < 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
n * n + n = m0 * 2 + n0, n0 < 2, m0 ≤ n ⊦ n = 1, n = 0, m0 = 1, m0 = 0

Rule argument

Additional information

Used simplifier rules: twols-02: ⊦ m ≠ 0 → (m < 2 ↔ m = 1); from specification nat-basic1