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Proof step 5 from proof two-loup-12 (previous step)

m + n = m0 * 2 + n0, n0 < 2 ⊦ m0 < n ↔ m < n

User applied rule cut formula

And obtained the following new goals

Proof step 6:
n0 = 0, m + n = m0 * 2 + n0, n0 < 2 ⊦ m0 < n ↔ m < n
Proof step 8:
m + n = m0 * 2 + n0, n0 < 2 ⊦ n0 = 0, m0 < n ↔ m < n

Rule argument

fma: n0 = 0

Additional information

Used formulas: n0 = 0