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Proof step 4 from proof two-ppred (previous step)

m = m0 * 2 + n0 ∧ n0 < 2 ∧ 2 ≠ 0 ⊦ m0 = (m - 2) / 2 + 1, m = 1, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n0 < 2 ⊦ m0 = (m0 * 2 + n0 - 2) / 2 + 1, m0 * 2 + n0 = 0, m0 = 0 ∧ n0 = 1

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-one-01: ⊦ 2 * m ≠ 1; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%zero-06: ⊦ m ≠ 0 → (m * n = 0 ↔ n = 0); from specification nat-mult%one: ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1; from specification nat-basic2