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Proof step 4 from proof two-zero-01-01 (previous step)

m = m0 * 2 + n0 ∧ n0 < 2 ∧ 2 ≠ 0 ⊦ m0 = 0 ↔ m = 0 ∨ m = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n0 < 2 ⊦ m0 = 0 ↔ m0 * 2 + n0 = 0 ∨ m0 * 2 + n0 = 1

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1