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Proof step 1 from proof div2-elim (conclusion)

⊦ odd(n) → (m = n / 2 ↔ n = m + m + 1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: pot2-odd-02: ⊦ n / 2 * 2 + 1 = n ↔ odd(n);%Odd: ⊦ odd(n) ↔ ¬ even(n);%oe-01: ⊦ odd(n) → ¬ even(n);%two-mdiv2-03: ⊦ (2 * m + 1) / 2 = m; from specification nat-div%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-02: ⊦ m + m = 2 * m; from specification nat-mult